On Fri, 24 Oct 2025 14:28:31 GMT, Raffaello Giulietti <[email protected]> 
wrote:

> Here's a way to aim at the correctly rounded result, maybe only upon request 
> because of the additional costs.
> 
> Let y = x^(1/n) (mathematically exact), yp = rootn(x, n) (approximation), and 
> assume the existence of nextHalfUp(decimal) and nextHalfDown(decimal).
> 
> pseudo code for any rounding-to-nearest mode and for n > 0 (monotonically 
> increasing function)
> 
> ```
> cmp = compare(yp^n, x)
> if cmp = 0 then return yp
> elsif cmp < 0 then
>     while nextHalfUp(yp)^n ≤ x do yp := nextUp(yp) od
>     return yp or nextDown(yp), depending on specific rounding mode
> else
>     while nextHalfDown(vp)^n ≥ x do yp := nextDown(yp) od
>     return yp or nextUp(yp), depending on specific rounding mode
> fi
> ```
> 
> There are various ways to improve this sketchy code.
> 
> Similar corrective actions could be defined for the other rounding modes and 
> for n < 0 (monotonically decreasing function).
> 
> @fabioromano1 @jddarcy WDYT? Is it worth adding correct rounding upon request?

I had the same idea, quite tricky to implement though.

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PR Comment: https://git.openjdk.org/jdk/pull/27148#issuecomment-3443754980

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