Collections.max(List.of(a, b))? On Tue, May 13, 2025 at 7:12 PM Tagir Valeev <amae...@gmail.com> wrote:
> The alternatives we have now: > BinaryOperator.maxBy(Comparator.<T>naturalOrder()).apply(a, b); > This speaks clearly about the intent (we'd like to get the maximum and we > write 'maxBy') but very wordy. > > Stream.of(a, b).max(Comparator.naturalOrder()).get(); > Also clear and a little bit shorter, but has an unnecessary Optional > in-between (we know that we have at least one element, so the result is > always present) and we have to mention the comparator. Finally, it might be > much less efficient than expected. >
