Nuno Milheiro wrote:
Given random play, komi value does not change play, so we could see
what is the mean score (no komi) instead of playing games at different
komis. But in this case we should not see those 2 exceptions.
Or else I'm wrong somewhere on my assumption.
You are wrong two ways.
First, the exceptions are normal: they are noise. The probabilities of
winning for 3.5 and 4.5 are the same.
Also, you cannot deduce winning percentage from mean score. For instance
+1 +1 -1 and +3 -1 -1 have the same mean score.
Rémi
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