On Aug 30, 2011, at 10:30 PM, Guy Halford-Thompson wrote: > I have created the window in IB and also created a custom class > (MyWindow). in IB I have given the window class MyWindow. > > I have added a couple of extra functions to MyWindow and now I wish to > trigger the window to be displayed given certain conditions. > > How can I display the window?
You need to know which object is being called when the condition is met, and that object has to have a pointer to your window so it can call it. Generally you’d wire a connection in Interface Builder from that object to your window, so the object will have an instance variable pointing to the window. In a simple app the object that’s doing stuff is most likely the application delegate object, so you’d add an instance variable of type MYWindow*, put the IBOutlet keyword on it so IB knows it can be wired to, and then control-drag a connection from the window to the app delegate. Now when a method of the app delegate is called (like some menu-triggered action) it can use that instance variable to call the window. —Jens_______________________________________________ Cocoa-dev mailing list (Cocoa-dev@lists.apple.com) Please do not post admin requests or moderator comments to the list. Contact the moderators at cocoa-dev-admins(at)lists.apple.com Help/Unsubscribe/Update your Subscription: http://lists.apple.com/mailman/options/cocoa-dev/archive%40mail-archive.com This email sent to arch...@mail-archive.com
