On Tue, Oct 5, 2010 at 8:20 AM, Kyle Sluder <[email protected]> wrote:
> The arithmetic conversion rules say that the integer literals will be
> promoted to the appropriate floating point type. So this is perfectly
> fine and does exactly what you expect:
P.S. The promotion doesn't only apply to literals but to other
expressions too. So your second casting example is unnecessary as
well. Compile this with -Wall -Werror to see that is is perfectly
valid C:
#include <stdio.h>
int main(int argc, char **argv) {
float x = 2.5;
int y = 5;
x += y;
printf("%f\n", x); // prints "7.500000"
return 0;
}
--Kyle Sluder
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