On Tue, Oct 5, 2010 at 8:16 AM, Shawn Bakhtiar <shashan...@hotmail.com> wrote:
>
>
> Eh?
>
> Did you just call typecasting "*completely* unnecessary and pointless"...
No, he called the specific casting you were performing unnecessary and
pointless, which it is.
The arithmetic conversion rules say that the integer literals will be
promoted to the appropriate floating point type. So this is perfectly
fine and does exactly what you expect:
int main(int argc, char **argv) {
float x = 2.5;
x += 5;
printf("%f\n", x); // prints "7.500000"
return 0;
}
--Kyle Sluder
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