On Mon, Oct 6, 2008 at 1:00 AM, Andrew Farmer <[EMAIL PROTECTED]> wrote:
> On 06 Oct 08, at 00:49, Gerriet M. Denkmann wrote:
>>
>> In the old days I wrote:
>>
>> int i; float f;
>> for( i = 0, f = 0.0; i < 5; i++, f+= 3.5 ) .....
>>
>> Now I am trying to use the C99 style:
>> for( int i = 0, float f = 0.0; i < 5; i++, f+= 3.5 ) .....
>> But I am told: "parse error before 'float'".
>>
>> Then I tried:
>> float f;
>> for( int i = 0, f = 0.0; i < 3; i++, f += 3.5 ) { printf("%g",f); };
>> But got: format '%g' expects type 'double', but argument 2 has type 'int'
>> and: unused variable 'f'
>>
>> So: how to declare two variables of different type which are to be valid
>> only in a for-loop?
>
> You can't. The C99 spec only allows you to make a single variable
> declaration in a loop. If you need to declare multiple variables, do that
> outside the loop.
FYI: You *can* declare multiple variables in the for loop, but they
all have to be the same type:
for(int i = 0, j = 10; i < j; ++i) {
}
--
Clark S. Cox III
[EMAIL PROTECTED]
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