On 06 Oct 08, at 00:49, Gerriet M. Denkmann wrote:
In the old days I wrote:
int i; float f;
for( i = 0, f = 0.0; i < 5; i++, f+= 3.5 ) .....
Now I am trying to use the C99 style:
for( int i = 0, float f = 0.0; i < 5; i++, f+= 3.5 ) .....
But I am told: "parse error before 'float'".
Then I tried:
float f;
for( int i = 0, f = 0.0; i < 3; i++, f += 3.5 ) { printf("%g",f); };
But got: format '%g' expects type 'double', but argument 2 has type
'int'
and: unused variable 'f'
So: how to declare two variables of different type which are to be
valid only in a for-loop?
You can't. The C99 spec only allows you to make a single variable
declaration in a loop. If you need to declare multiple variables, do
that outside the loop.
(The warnings in your second example are because you declared two
variables named "f" - one float in the outer context, and an integer
in the for-loop context which shadows the float.)
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