Indeed, I think this is the same as m = 2w/sin(a). But for worst case
bounds, the angle itself doesn't need to be measured or known, only
the miter limit.
Thanks for your help!
cheers, Graham
On 9 Jul 2008, at 4:34 pm, Peter Zegelin wrote:
Cool I got it right - finally! Its on page 154 of the spec (174 in
PDF viewer) section 4.3.
Me in another post "I believe the fully correct answer to calculate
the extension is: (strokeWidth/2)/ sin(angle/2);"
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