For the sake of completeness, the second line was incorrect (bracket
preceding NSCalendar). It has been corrected in the following snippet:
On 02/07/2008, at 10:41 AM, mmalc crawford wrote:
NSDate *today = [NSDate date];
NSCalendar *gregorian = [[NSCalendar alloc]
initWithCalendarIdentifier:NSGregorianCalendar];
// Get the weekday component of the current date
NSDateComponents *weekdayComponents = [gregorian
components:NSWeekdayCalendarUnit fromDate:today];
/*
Create a date components to represent the number of days to subtract
from the current date.
The weekday value for Sunday in the Gregorian calendar is 1, so
subtract 1 from the number
of days to subtract from the date in question. (If today's Sunday,
subtract 0 days.)
*/
NSDateComponents *componentsToSubtract = [[NSDateComponents alloc]
init];
[componentsToSubtract setDay: - ([weekdayComponents weekday] - 1)];
NSDate *beginningOfWeek = [gregorian
dateByAddingComponents:componentsToSubtract toDate:today options:0];
/*
Optional step:
beginningOfWeek now has the same hour, minute, and second as the
original date (today).
To normalize to midnight, extract the year, month, and day
components and create a new date from those components.
*/
NSDateComponents *components = [gregorian components:
(NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit)
fromDate: beginningOfWeek];
beginningOfWeek = [gregorian dateFromComponents: components];
JJ
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