The first thing that jumps out at me are the boxed numbers: 0N and 1N.  I'm 
guessing the Clojure implementation can produce a much larger result than 
the python implementation can - so, apples to oranges.  Probably unbox the 
numbers and you get much more comparable speed.

Also, you should definitely do two things when running speed comparisons:

1. Make sure the JVM flag -server is configured.
2. Test with Criterium.  (https://github.com/hugoduncan/criterium)

On Wednesday, December 31, 2014 2:03:03 PM UTC-6, Sakis K wrote:
>
> Hi,
>
> Clojure newbie here :) I'm reading "Programming Clojure" by Halloway and 
> Bedra. In the book there is a lazy-seq example of the Fibonacci sequence:
>
> (defn lazy-seq-fibo
>   ([]
>      (concat [0 1] (lazy-seq-fibo 0N 1N)))
>   ([a b]
>      (let [n (+ a b)]      
>        (lazy-seq                       
>         (cons n (lazy-seq-fibo b n))))))
>
>
> I like the flexibility of this implementation but I am a bit sceptical 
> about its performance:
>
> user=> (time (rem (nth (lazy-seq-fibo) 1000000) 1000))
> "Elapsed time: 53552.014713 msecs"
> 875N
>
>
>
> Here's a Python implementation taken from 
> http://en.literateprograms.org/Fibonacci_numbers_%28Python%29
>
> def fib(n):
>     a, b = 0, 1
>     for i in range(n):
>         a, b = b, a + b
>     return a
>
> if __name__ == '__main__':
>     print(fib(1000000) % 1000)
>
>
> time python fib.py 
> 875
>
> real    0m16.609s
> user    0m16.475s
> sys     0m0.115s
>
>
> 53 vs 17 seconds is a big gap. Is there a way to achieve better 
> performance in Clojure? Maybe the fact that I executed the code in the REPL 
> or the Java version that I'm using matters:
> java -version
> java version "1.7.0_65"
> OpenJDK Runtime Environment (IcedTea 2.5.3) (7u71-2.5.3-0ubuntu1)
> OpenJDK 64-Bit Server VM (build 24.65-b04, mixed mode)
>
>

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