Updated the gist to fix a case '(:a :b) should've returned '((:a :b)) to match partition-by.
New: The sub-seq can optionally contain fns, just like partition-by's f param. ;; Case: using a seq of fns instead of values (= (partition-by-seq [odd? odd? even?] [1 2 3 5 6 7 8 9 11 12]) '((1 2) (3 5 6) (7 8) (9 11 12))) ;; Case: compare using a mix of fns and values (= (partition-by-seq [odd? 10] [1 10 2 10 3 10 4 10 5 10 6]) '((1 10) (2 10) (3 10) (4 10) (5 10) (6))) On Sunday, June 8, 2014 11:27:12 AM UTC-5, Alex Walker wrote: > > https://gist.github.com/alexpw/f20c7b3ac858003e07e2 > > This version supports the missing case: > > ;; Case: false match :b, followed by true match :b :c > (= (partition-by-seq [:b :c] [:a :b :b :c :e :d :a :b :c :d :a :b :c]) > '((:a :b) (:b :c) (:e :d :a) (:b :c) (:d :a) (:b :c))) > > > On Sunday, June 8, 2014 8:52:09 AM UTC-5, Alex Walker wrote: >> >> Err, this was bugging me all day when I went afk. I wrote it too quickly >> and am missing the case where the sub-seq starts right after seeing the >> first val, [:b :b :c]. >> >> Will fix it if I have time today, but may need to take a slightly >> different approach. Fun problem, btw. :) >> >> On Saturday, June 7, 2014 2:31:04 PM UTC-5, Alex Walker wrote: >>> >>> Here's a solution based on your description that behaves like core >>> partition fns, taking liberty to presume your example should've matched the >>> output below. >>> >>> (defn partition-by-seq >>> [sub-seq coll] >>> (letfn [(step [coll] >>> (when-let [coll (seq coll)] >>> (let [[run more] (split-with (partial not= (first sub-seq)) >>> coll) >>> [possible-match more] (split-at (count sub-seq) more)] >>> (if (= possible-match sub-seq) >>> (if (seq run) >>> (cons run (cons possible-match (lazy-seq (step >>> more)))) >>> (cons possible-match (lazy-seq (step >>> more)))) >>> (cons (concat run possible-match) (lazy-seq (step >>> more)))))))] >>> (or (step coll) ()))) >>> >>> => (partition-by-seq [:b :c] []) >>> >>> () >>> >>> => (partition-by-seq [:b :c] [:a :d]) >>> >>> ((:a :d)) >>> >>> => (partition-by-seq [:b :c] [:a :b :c :d :a :b :c :d :a :b :c]) >>> >>> ((:a) (:b :c) (:d :a) (:b :c) (:d :a) (:b :c)) >>> >>> >>> >>> On Tuesday, June 3, 2014 4:05:16 AM UTC-5, Ulrich Küttler wrote: >>>> >>>> Hi, >>>> >>>> what is the preferred way to find sub-seqs in a seq? I am trying to >>>> convert >>>> >>>> [:a :b :c :d :a :b :c :d :a :b :c] >>>> >>>> into >>>> >>>> ((:a) (:b :c) (:a :d) (:b :c) (:a)) >>>> >>>> using the sub-seq (:b :c) instead of positions. >>>> >>>> partition, partition-by and the like all look at one element at a time. >>>> What I need is a search based on seqs. Are there functions that support >>>> such a search / split? >>>> >>>> Uli >>>> >>> -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en --- You received this message because you are subscribed to the Google Groups "Clojure" group. To unsubscribe from this group and stop receiving emails from it, send an email to clojure+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.