Ah, scratch that, list* returns a seq as well.
On Fri, May 2, 2014 at 11:07 AM, Gary Trakhman <gary.trakh...@gmail.com>wrote:
> I believe what he wants is a persistentlist. You could get one from
> (apply list) or more succinctly/esoterically (list* ..)
>
> Sort returns a seq view over the array returned by java.util.Array.sort()
>
> (defn sort
>
> "Returns a sorted sequence of the items in coll. If no comparator is
> supplied, uses compare. comparator must
> implement java.util.Comparator."
> {:added "1.0"
> :static true}
> ([coll]
> (sort compare coll))
> ([^java.util.Comparator comp coll]
> (if (seq coll)
> (let [a (to-array coll)]
> (. java.util.Arrays (sort a comp))
> (seq a))
> ())))
>
>
> (class (sort (range 10)))
> clojure.lang.ArraySeq
>
>
> On Fri, May 2, 2014 at 11:01 AM, Plínio Balduino <pbaldu...@gmail.com>wrote:
>
>> Hi Dave
>>
>> Sorry if I didn't get it, but doesn't sort already return a list?
>>
>> Could explain?
>>
>> Plínio
>>
>>
>>
>> On Fri, May 2, 2014 at 11:53 AM, Dave Tenny <dave.te...@gmail.com> wrote:
>>
>>> I have a sequence from a call to 'sort'.
>>> I want a list.
>>>
>>> What is the best way to do this?
>>>
>>> (apply list (sort ...))?
>>>
>>> Will it have problems on large sequence inputs?
>>>
>>>
>>> I can't use (into () (sort ...))
>>> since that conjoins and ruins the sort order.
>>>
>>>
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>
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