I believe what he wants is a persistentlist. You could get one from (apply
list) or more succinctly/esoterically (list* ..)
Sort returns a seq view over the array returned by java.util.Array.sort()
(defn sort
"Returns a sorted sequence of the items in coll. If no comparator is
supplied, uses compare. comparator must
implement java.util.Comparator."
{:added "1.0"
:static true}
([coll]
(sort compare coll))
([^java.util.Comparator comp coll]
(if (seq coll)
(let [a (to-array coll)]
(. java.util.Arrays (sort a comp))
(seq a))
())))
(class (sort (range 10)))
clojure.lang.ArraySeq
On Fri, May 2, 2014 at 11:01 AM, Plínio Balduino <pbaldu...@gmail.com>wrote:
> Hi Dave
>
> Sorry if I didn't get it, but doesn't sort already return a list?
>
> Could explain?
>
> Plínio
>
>
>
> On Fri, May 2, 2014 at 11:53 AM, Dave Tenny <dave.te...@gmail.com> wrote:
>
>> I have a sequence from a call to 'sort'.
>> I want a list.
>>
>> What is the best way to do this?
>>
>> (apply list (sort ...))?
>>
>> Will it have problems on large sequence inputs?
>>
>>
>> I can't use (into () (sort ...))
>> since that conjoins and ruins the sort order.
>>
>>
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