2014-04-12 15:06 GMT+02:00 Fergal Byrne <fergalbyrnedub...@gmail.com>:
> For precise timing benchmarks, use criterium [1].
> For simple, gross timing, use
>
> (map #(time (foo %)) numbers)
>
That is not going to work, time prints the time instead of giving it back.
or to convert your code to something more functional (and including defns
> for now and foo):
>
>
> (defn now [] (. System currentTimeMillis))
>
I already defined it as:
(defn now []
(new java.util.GregorianCalendar))
I use it for other things also.
> (def numbers '(4 6 8 10))
>
> (defn foo [n] (reverse (map #(* % %) (range (Math/pow n 5)))))
>
> (count (foo 10))
>
> (defn timed-foo [times n]
> (let [start (now)]
> (foo n)
> (conj times (- (now) start))))
>
> (reduce timed-foo [] numbers) => [0 0 4 14]
>
I am going to look into this.
> On Sat, Apr 12, 2014 at 1:13 PM, Cecil Westerhof
> <cldwester...@gmail.com>wrote:
>
>> At the moment I have the following:
>> (def numbers '(4 6 8 10))
>>
>> (doseq [number numbers]
>> (foo number))
>>
>> The call foo generates some output, but I also want to save the time it
>> took for the call to complete. At the moment I am thinking about
>> something like:
>> (def numbers '(4 6 8 10))
>>
>> (def ^:dynamic needed-times ())
>> (doseq [number numbers]
>> (let [start (now)]
>> (foo number)
>> (def ^:dynamic needed-times
>> (cons (- (.getTimeInMillis (now))
>> (.getTimeInMillis start))
>> needed-times))))
>>
>> But it looks a 'little' cumbersome. Is there a better way to do this?
>>
>> Also if I need to use several points in time, do I keep nesting 'let',
>> or is there a better way?
>>
>
--
Cecil Westerhof
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