Hey guys, here is a huge performance problem I'm trying to figure out:
;; Say you have 2 data arrays sitting out there of 1 MB
(def one-mb (byte-array (* 1024 1024)))
(def another-mb (byte-array (* 1024 1024)))
;; and another one that should have the byte-by-byte XOR of the previous
two
(def out-mb (byte-array (* 1024 1024)))
;; question is... how do you code this guy, so that it doesn't take forever
(defn inplace-xor [a b out]
(def ln (count a))
(loop [x 0]
(if (< x ln)
(do
(aset-byte out x (bit-xor (nth a x) (nth b x)))
(recur (+ x 1))
))))
;; checking the time
(time (inplace-xor one-mb another-mb out-mb))
;; takes about ~400ms which is.... well... A LOT
;; I'm happy to receive a solution that involves calling some java
library...
Thanks in advance!
-Ignacio
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