Ok thanks, thats really helpful. The second link suggests using doall, 
which seems to do the trick :

((fn pascal ([n] (pascal n [1M])) ([n row] (if (= n 1) row (recur (dec n) 
(map (partial reduce +) (doall (partition 2 1 (concat [0] row [0])))))))) 
500)

However you do lose the laziness, but here the laziness is not needed ...

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