I wonder if the somewhat counterintuitive concept of a "named anonymous 
function" eludes some people, or isn't properly conveyed in tutorials.

On Tuesday, 27 August 2013 00:36:07 UTC-7, HamsterofDeath wrote:

> thx
>
>
> 2013/8/26 Marshall Bockrath-Vandegrift <lla...@gmail.com <javascript:>>
>
>> Dennis Haupt <d.ha...@gmail.com <javascript:>> writes:
>>
>> > (defn fib-n [n]
>> > (let [fib (fn [a b] (cons a (lazy-seq (fib b (+ b a)))))]
>> > (take n (fib 1 1))))
>> >
>> > can't i do a recursion here? how can i achieve this without doing an
>> > "outer defn"?
>>
>> You just need to give the anonymous function a name it can use to refer
>> to itself for (non-tail) recursion:
>>
>>     (defn fib-n [n]
>>       (let [fib (fn fib [a b] (cons a (lazy-seq (fib b (+ b a)))))]
>>         (take n (fib 1 1))))
>>
>> -Marshall
>>
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