Thanks guys.... i have now have a bunch of solutions to try out ;)

Josh


On Thu, Jun 13, 2013 at 8:57 PM, Aaron Cohen <aa...@assonance.org> wrote:

> I like the StackOverflow answer for this:
>
>
> http://stackoverflow.com/questions/5419125/using-java-api-from-clojure-reading-zip-file
>
> (defn entries [zipfile]
>   (enumeration-seq (.entries zipfile)))
> (defn walkzip [fileName]
>   (with-open [z (java.util.zip.ZipFile. fileName)]
>              (doseq [e (entries z)]
>                     (println (.getName e)))))
>
>
>
> On Thu, Jun 13, 2013 at 1:25 PM, Leon Barrett <lbarr...@climate.com>wrote:
>
>> Yeah, Clojure's while construct isn't really good at stuff like that. A
>> loop is the basic thing I reach for, and I'd probably write it as:
>>
>> (loop []
>>   (when-let [entry (.getNextEntry stream)]
>>     (println entry)
>>     (recur)))
>>
>>
>> On Thursday, June 13, 2013 10:20:22 AM UTC-7, Josh Kamau wrote:
>>>
>>> Hi there ;
>>>
>>> How do i implement the following in clojure
>>>
>>>     while((entry = stream.getNextEntry())!=null)   {
>>>
>>>        System.out.println(entry.**getName());
>>>
>>>   }
>>>
>>> NOTE: calling getNextEntry moves the curse to the next entry.
>>>
>>> CONTEXT: I am trying to list the contents of a .zip file using 
>>> http://docs.oracle.com/javase/**6/docs/api/java/util/zip/**ZipInputStream.html
>>>  
>>> <http://docs.oracle.com/javase/6/docs/api/java/util/zip/ZipInputStream.html>
>>>
>>>
>>> Regards.
>>>
>>> Josh
>>>
>>>
>>>           --
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