I like the StackOverflow answer for this:
http://stackoverflow.com/questions/5419125/using-java-api-from-clojure-reading-zip-file
(defn entries [zipfile]
(enumeration-seq (.entries zipfile)))
(defn walkzip [fileName]
(with-open [z (java.util.zip.ZipFile. fileName)]
(doseq [e (entries z)]
(println (.getName e)))))
On Thu, Jun 13, 2013 at 1:25 PM, Leon Barrett <lbarr...@climate.com> wrote:
> Yeah, Clojure's while construct isn't really good at stuff like that. A
> loop is the basic thing I reach for, and I'd probably write it as:
>
> (loop []
> (when-let [entry (.getNextEntry stream)]
> (println entry)
> (recur)))
>
>
> On Thursday, June 13, 2013 10:20:22 AM UTC-7, Josh Kamau wrote:
>>
>> Hi there ;
>>
>> How do i implement the following in clojure
>>
>> while((entry = stream.getNextEntry())!=null) {
>>
>> System.out.println(entry.**getName());
>>
>> }
>>
>> NOTE: calling getNextEntry moves the curse to the next entry.
>>
>> CONTEXT: I am trying to list the contents of a .zip file using
>> http://docs.oracle.com/javase/**6/docs/api/java/util/zip/**ZipInputStream.html
>> <http://docs.oracle.com/javase/6/docs/api/java/util/zip/ZipInputStream.html>
>>
>>
>> Regards.
>>
>> Josh
>>
>>
>> --
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