Wouldn't (remove :dh-uuid (apply concat (map find-records query-parts))) be
better?


On Sat, May 25, 2013 at 1:09 PM, Mond Ray <mondraym...@gmail.com> wrote:

> Bingo:
>
> user=> (filter (complement :dh-uuid) (apply concat (map find-records
> query-parts)))
> ({:a2p-id "3", :dh-uuid nil} {:a2p-id "3", :dh-uuid nil})
>
> Thanks everyone!
>
>
> On Saturday, 25 May 2013 19:29:55 UTC+2, Andy Fingerhut wrote:
>
>> Woops, and here I wasn't being careful enough...  You have a list (or
>> sequence) of two elements, both of which are lists (or sequences) of maps.
>> You can use (apply concat (map find-records query-parts)) to return a
>> single list containing nothing but maps.
>>
>> Andy
>>
>>
>> On Sat, May 25, 2013 at 10:27 AM, Andy Fingerhut <andy.fi...@gmail.com>wrote:
>>
>>> If (map find-records query-parts) is returning this expression:
>>>
>>>
>>> (({:a2p-id "1", :dh-uuid "abc-def-ghi-klm"} {:a2p-id "2", :dh-uuid
>>> "def-ghi-klm-opq"} {:a2p-id "3", :dh-uuid nil}) ({:a2p-id "1", :dh-uuid
>>> "abc-def-ghi-klm"} {:a2p-id "2", :dh-uuid "def-ghi-klm-opq"} {:a2p-id "3",
>>> :dh-uuid nil}))
>>>
>>> then especially note the double parentheses.  That is a list (or
>>> sequence), whose first element is a list (or sequence) of maps.  You can
>>> use (first (map find-records query-parts)) to get the inner list.
>>>
>>> Andy
>>>
>>>
>>> On Sat, May 25, 2013 at 4:21 AM, Mond Ray <mondr...@gmail.com> wrote:
>>>
>>>> I am missing something obvious... I get a list of maps back from a
>>>> function and I want to find the elements with nil
>>>>
>>>> (({:a2p-id "1", :dh-uuid "abc-def-ghi-klm"} {:a2p-id "2", :dh-uuid
>>>> "def-ghi-klm-opq"} {:a2p-id "3", :dh-uuid nil}) ({:a2p-id "1", :dh-uuid
>>>> "abc-def-ghi-klm"} {:a2p-id "2", :dh-uuid "def-ghi-klm-opq"} {:a2p-id "3",
>>>> :dh-uuid nil}))
>>>>
>>>> I try the select function but it has no effect ... same list
>>>>
>>>> (set/select #(not (:dh-uuid %)) (map find-records query-parts))
>>>>
>>>> also tried the previously working example... same list
>>>>
>>>> (filter #(not (:dh-uuid %)) (map find-records query-parts))
>>>>
>>>> I am assuming that I am not indexing into each of the maps but I cannot
>>>> remember or find out how to do this ... all examples only show one map
>>>>
>>>> Thanks
>>>>
>>>> Ray
>>>>
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>>>
>>>
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