Woops, and here I wasn't being careful enough... You have a list (or
sequence) of two elements, both of which are lists (or sequences) of maps.
You can use (apply concat (map find-records query-parts)) to return a
single list containing nothing but maps.
Andy
On Sat, May 25, 2013 at 10:27 AM, Andy Fingerhut
<andy.finger...@gmail.com>wrote:
> If (map find-records query-parts) is returning this expression:
>
>
> (({:a2p-id "1", :dh-uuid "abc-def-ghi-klm"} {:a2p-id "2", :dh-uuid
> "def-ghi-klm-opq"} {:a2p-id "3", :dh-uuid nil}) ({:a2p-id "1", :dh-uuid
> "abc-def-ghi-klm"} {:a2p-id "2", :dh-uuid "def-ghi-klm-opq"} {:a2p-id "3",
> :dh-uuid nil}))
>
> then especially note the double parentheses. That is a list (or
> sequence), whose first element is a list (or sequence) of maps. You can
> use (first (map find-records query-parts)) to get the inner list.
>
> Andy
>
>
> On Sat, May 25, 2013 at 4:21 AM, Mond Ray <mondraym...@gmail.com> wrote:
>
>> I am missing something obvious... I get a list of maps back from a
>> function and I want to find the elements with nil
>>
>> (({:a2p-id "1", :dh-uuid "abc-def-ghi-klm"} {:a2p-id "2", :dh-uuid
>> "def-ghi-klm-opq"} {:a2p-id "3", :dh-uuid nil}) ({:a2p-id "1", :dh-uuid
>> "abc-def-ghi-klm"} {:a2p-id "2", :dh-uuid "def-ghi-klm-opq"} {:a2p-id "3",
>> :dh-uuid nil}))
>>
>> I try the select function but it has no effect ... same list
>>
>> (set/select #(not (:dh-uuid %)) (map find-records query-parts))
>>
>> also tried the previously working example... same list
>>
>> (filter #(not (:dh-uuid %)) (map find-records query-parts))
>>
>> I am assuming that I am not indexing into each of the maps but I cannot
>> remember or find out how to do this ... all examples only show one map
>>
>> Thanks
>>
>> Ray
>>
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