Reading the source, Ratios are actually represented as
java.math.BigIntegerobjects. (
https://github.com/clojure/clojure/blob/master/src/jvm/clojure/lang
/Ratio.java)

Asking for denominator and numerator returns these values directly.
user=> (class (denominator (/ 1 2)))
java.math.BigInteger
user=> (class (numerator (/ 1 2)))
java.math.BigInteger

Following the source, conversion happens in the Numbers.divide(BigInteger,
BigInteger) method:
https://github.com/clojure/clojure/blob/master/src/jvm/clojure/lang
/Numbers.java#L342
(called from https://github.com/clojure/clojure/blob/master/src/jvm/clojure/
lang/Numbers.java#L670)

Cheers,
Alf



On 1 April 2013 23:57, Alan Thompson <thompson2...@gmail.com> wrote:

> Just read about this in "Clojure Programming" (Emerick) p428:
>  clojure.lang.BigInt is different than java.lang.BigInteger, in that BigInt
> uses 64-bit primitive longs under the covers to keep performance up if the
> value will fit within the range of a long.  So for "normal" sized values,
> it doesn't have the overhead of the arbitrary-precision type.  But, the
> extra precision is there if you need it later on in a calculation.
>  Alan Thompson
>
>
>
> On Mon, Apr 1, 2013 at 2:43 PM, Gary Verhaegen 
> <gary.verhae...@gmail.com>wrote:
>
>> That's because ratios are intended to get you arbitrary precision.
>> That would not work so well if they used Longs for their numerator and
>> denominator.
>>
>> On 29 March 2013 14:11, Peter Mancini <peter.manc...@gmail.com> wrote:
>> > (class 1) java.lang.Long ;check!
>> > (class (* (/ 1 255) 254)) clojure.lang.Ratio ;check!
>> > (class (* (/ 1 255) 255)) clojure.lang.BigInt ;WAT?
>> >
>> > Should not example 3 and example 1 end up the same? (Noob question, I
>> know,
>> > but this didn't make sense to me and I thought I was doing something
>> wrong
>> > when I saw 1N coming back.)
>> >
>
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