On Sat, Aug 11, 2012 at 2:14 PM, Moritz Ulrich <mor...@tarn-vedra.de> wrote:
>
> Hi, fellow logic programmers!
>
>
> Shouldn't `membero' work with sets?
>
> I notice that
>
> (run* [q] (membero :x #{:x}))
>
> returns no results while
>
> (run* [q] (membero :x (seq #{:x})))
>
> returns the (in my opinion) correct result: (:x).
>
>
> Can someone explain this behavior to me? It seems strange.
>
> --
> Moritz Ulrich
It doesn't work with sets. And it can't. If you want to understand
why: look at the implementation of membero and look at an
implementation of member in Prolog.
David
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