Hi, fellow logic programmers!
Shouldn't `membero' work with sets?
I notice that
(run* [q] (membero :x #{:x}))
returns no results while
(run* [q] (membero :x (seq #{:x})))
returns the (in my opinion) correct result: (:x).
Can someone explain this behavior to me? It seems strange.
--
Moritz Ulrich
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