Cool! That's a very compact implementation.
Could the same technique be adapted to give you the longest common
substring?
e.g. (foo "fooba" "baab") => "ba"
Or better yet, the length of the longest common substring and the starting
indices of each common substring of that length,
e.g. (foo "baaboobaa" "baa") => {:length 3, :indices #{0 6}}
-Stuart Sierra
clojure.com
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