Since (repeat) returns a lazy sequence, and partition will only take as many as is needed, I think you don't even have to specify how many times to repeat:
user=> (partition 3 3 (repeat "a") [1 2 3 4 5 6 7]) ((1 2 3) (4 5 6) (7 "a" "a")) And if the desired behavior is to repeat the last element of provided padding as many times as necessary, you could do it with a little helper function: (defn pad-padding [padding] (concat padding (repeat (last padding)))) user=> (partition 4 4 (pad-padding ["a" "b"]) [1 2 3 4 5 6 7 8 9]) ((1 2 3 4) (5 6 7 8) (9 "a" "b" "b")) On Nov 23, 12:05 am, Meikel Brandmeyer <m...@kotka.de> wrote: > Hi, > > while not having looked at your code, partition does what you want: > > user=> (partition 3 3 (repeat 3 "a") [1 2 3 4 5 6 7]) > ((1 2 3) (4 5 6) (7 "a" "a")) > user=> (partition 3 3 (repeat 3 "a") [1 2 3 4 5 6 7 8]) > ((1 2 3) (4 5 6) (7 8 "a")) > user=> (partition 3 3 (repeat 3 "a") [1 2 3 4 5 6 7 8 9]) > ((1 2 3) (4 5 6) (7 8 9)) > user=> (partition 3 3 (repeat 3 "a") [1 2 3 4 5 6 7 8 9 10]) > ((1 2 3) (4 5 6) (7 8 9) (10 "a" "a")) > > (Note: the 3 in repeat is not strictily necessary. 2 would be > sufficient) > > Sincerely > Meikel -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
