Hi Meikel,

What I want to accomplish is to have the function 'fill the gap' if
not enough padding is supplied.

With the standard 'partition' function this does not work, as it only
adds as much padding as provided:

(partition 3 3 ["a"] [1 2 3 4 5 6 7 8 9 10])
;; ((1 2 3) (4 5 6) (7 8 9) (10 "a"))

I thought my implementation would solve this problem, but
unfortunately there is some bug in the code I haven't been able to
find.

Stefan


On Nov 23, 3:05 pm, Meikel Brandmeyer <m...@kotka.de> wrote:
> Hi,
>
> while not having looked at your code, partition does what you want:
>
> user=> (partition 3 3 (repeat 3 "a") [1 2 3 4 5 6 7])
> ((1 2 3) (4 5 6) (7 "a" "a"))
> user=> (partition 3 3 (repeat 3 "a") [1 2 3 4 5 6 7 8])
> ((1 2 3) (4 5 6) (7 8 "a"))
> user=> (partition 3 3 (repeat 3 "a") [1 2 3 4 5 6 7 8 9])
> ((1 2 3) (4 5 6) (7 8 9))
> user=> (partition 3 3 (repeat 3 "a") [1 2 3 4 5 6 7 8 9 10])
> ((1 2 3) (4 5 6) (7 8 9) (10 "a" "a"))
>
> (Note: the 3 in repeat is not strictily necessary. 2 would be
> sufficient)
>
> Sincerely
> Meikel

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