Leaving out the parentheses changes the meaning because they group as
well as capture. #"a(b|c)d" matches either "abd" or "acd". #"ab|cd"
matches either "ab" or "cd".
On Tuesday, March 30, 2010, Glen Rubin <rubing...@gmail.com> wrote:
> thx that works great! i guess I can also just leave out the
> parenthesis all together.
>
> but, what if i wanted just the portion inside?? the duplicate I
> wanted to get rid of?
>
> also any way to return the sequence without all those bars or do i
> have to use a seperate regex and or filter?
>
> On Mar 30, 12:52 pm, "Mark J. Reed" <markjr...@gmail.com> wrote:
>> Addendum: I highly recommend Jeffrey Friedl's book
>> _Mastering_Regular_Expressions_ if you want to learn how to use
>> regexes well. There are also a number of introductions/tutorials
>> online, but I'm not familiar enough with them to recommend any.
>>
>> On Tue, Mar 30, 2010 at 12:50 PM, Mark J. Reed <markjr...@gmail.com> wrote:
>>
>>
>>
>>
>>
>> > Parentheses capture - anything that matches a parenthesized portion of
>> > a regular expression is returned as part of the result of the match:
>>
>> > user=> (re-seq #"a(.)c" "abc")
>> > (["abc" "b"])
>>
>> > If you don't want that behavior, you can use the special non-capturing
>> > syntax, (?:...):
>>
>> > user=> (re-seq #"a(?:.)c" "abc")
>> > ("abc")
>>
>> > You don't have to escape pipes or any other special characters inside
>> > a character class (that is, between [...]), because characters lose
>> > their special meanings there: [.*] matches either a period or an
>> > asterisk and has no relationship to the "any character" symbol or
>> > "zero or more" repetition operator.
>>
>> > The only special things inside a character class are a leading '^',
>> > which negates the class, and a '-' in the middle, which makes a range:
>> > [^a-z] matches any single character that is not a lowercase letter (of
>> > the English alphabet). Position matters: [-^] matches a literal
>> > hyphen or caret, and [] is not an empty character class but a syntax
>> > error (an unclosed character class that so far includes a literal ']'
>> > character).
>>
>> > On Tue, Mar 30, 2010 at 12:37 PM, Glen Rubin <rubing...@gmail.com> wrote:
>> >> The result is a little bit strange still, since I am getting
>> >> dupliates. First, it returns the string I want
>>
>> >> 49|00|12 .... 12|a9|a4|ff
>>
>> >> but then it also returns the same string without the first and last 4
>> >> characters, e.g.
>>
>> >> 12|....12|a9|
>>
>> >> Also, how come I don't need to escape the | inside the parenthesis?
>>
>> >> thanks Meikel!!
>>
>> >> On Mar 30, 10:59 am, Meikel Brandmeyer <m...@kotka.de> wrote:
>> >>> Hi,
>>
>> >>> you have to escape the |.
>>
>> >>> user=> (re-seq #"49\|00\|([0-9a-f|]+)\|a4\|ff" "a5|a5|49|23|49|00|12|
>> >>> fc|5e|a4|ff|a7|49|00|ee|d3|a4|ff|ae")
>> >>> (["49|00|12|fc|5e|a4|ff|a7|49|00|ee|d3|a4|ff" "12|fc|5e|a4|ff|a7|49|00|
>> >>> ee|d3"])
>>
>> >>> However this will be greedy...
>>
>> >>> Sincerely
>> >>> Meikel
>>
>> >> --
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>> > --
>> > Mark J. Reed <markjr...@gmail.com>
>>
>> --
>> Mark J. Reed <markjr...@gmail.com>
>
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--
Mark J. Reed <markjr...@gmail.com>
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