thx that works great! i guess I can also just leave out the
parenthesis all together.
but, what if i wanted just the portion inside?? the duplicate I
wanted to get rid of?
also any way to return the sequence without all those bars or do i
have to use a seperate regex and or filter?
On Mar 30, 12:52 pm, "Mark J. Reed" <markjr...@gmail.com> wrote:
> Addendum: I highly recommend Jeffrey Friedl's book
> _Mastering_Regular_Expressions_ if you want to learn how to use
> regexes well. There are also a number of introductions/tutorials
> online, but I'm not familiar enough with them to recommend any.
>
> On Tue, Mar 30, 2010 at 12:50 PM, Mark J. Reed <markjr...@gmail.com> wrote:
>
>
>
>
>
> > Parentheses capture - anything that matches a parenthesized portion of
> > a regular expression is returned as part of the result of the match:
>
> > user=> (re-seq #"a(.)c" "abc")
> > (["abc" "b"])
>
> > If you don't want that behavior, you can use the special non-capturing
> > syntax, (?:...):
>
> > user=> (re-seq #"a(?:.)c" "abc")
> > ("abc")
>
> > You don't have to escape pipes or any other special characters inside
> > a character class (that is, between [...]), because characters lose
> > their special meanings there: [.*] matches either a period or an
> > asterisk and has no relationship to the "any character" symbol or
> > "zero or more" repetition operator.
>
> > The only special things inside a character class are a leading '^',
> > which negates the class, and a '-' in the middle, which makes a range:
> > [^a-z] matches any single character that is not a lowercase letter (of
> > the English alphabet). Position matters: [-^] matches a literal
> > hyphen or caret, and [] is not an empty character class but a syntax
> > error (an unclosed character class that so far includes a literal ']'
> > character).
>
> > On Tue, Mar 30, 2010 at 12:37 PM, Glen Rubin <rubing...@gmail.com> wrote:
> >> The result is a little bit strange still, since I am getting
> >> dupliates. First, it returns the string I want
>
> >> 49|00|12 .... 12|a9|a4|ff
>
> >> but then it also returns the same string without the first and last 4
> >> characters, e.g.
>
> >> 12|....12|a9|
>
> >> Also, how come I don't need to escape the | inside the parenthesis?
>
> >> thanks Meikel!!
>
> >> On Mar 30, 10:59 am, Meikel Brandmeyer <m...@kotka.de> wrote:
> >>> Hi,
>
> >>> you have to escape the |.
>
> >>> user=> (re-seq #"49\|00\|([0-9a-f|]+)\|a4\|ff" "a5|a5|49|23|49|00|12|
> >>> fc|5e|a4|ff|a7|49|00|ee|d3|a4|ff|ae")
> >>> (["49|00|12|fc|5e|a4|ff|a7|49|00|ee|d3|a4|ff" "12|fc|5e|a4|ff|a7|49|00|
> >>> ee|d3"])
>
> >>> However this will be greedy...
>
> >>> Sincerely
> >>> Meikel
>
> >> --
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>
> > --
> > Mark J. Reed <markjr...@gmail.com>
>
> --
> Mark J. Reed <markjr...@gmail.com>
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