If this situation is common enough, shouldn't defprotocol support
optional implementations which are implicitly merged?

On Feb 9, 6:01 am, Konrad Hinsen <konrad.hin...@fastmail.net> wrote:
> On 09.02.2010, at 02:14, Stuart Sierra wrote:
>
> > On Feb 8, 6:13 pm, aria42 <ari...@gmail.com> wrote:
> >> (defprotocol Span
> >>   (start [self])
> >>   (stop [self])
> >>   (span-length [self]))
>
> >> Now I know I can just make span-length a function on Span as opposed
> >> to part of the protocol. Is that what one should do?
>
> > Yes.
>
> I would say "it depends".
>
> I have a similar situation in my multiarray package 
> (http://code.google.com/p/clj-multiarray/). In the multiarray protocol, I 
> have two functions, "shape" and "rank", with the latter being by definition 
> the same as (comp count shape). However, I still have "rank" in the protocol, 
> because for some implementations it is more efficient to compute the rank 
> directly, rather than construct a shape vector just for computing its length 
> afterwards.
>
> In such situations it is useful to provide a default implementation and leave 
> it up to each type to implement a more efficient alternative or not. With 
> extend and the maps that go with it, this is easy to achieve: make a map with 
> the default implementations, and merge this with the type-specific 
> implementations fed to extend.
>
> Konrad.

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