This is expected behavior. eg. (str (map identity [1 2 3])) returns "clojure.lang.lazy...@7861"
The way to think about it is, (str) asks for the string representation of an object. The string representation of a lazy sequence in this case is "clojure.lang.lazy...@7861". If you want the string representations of what's inside the lazy seq, you can use the apply function. (apply str (map identity [1 2 3])) "123" Alternatively, you can convert the lazy-seq to a vector. The string representation for a vector shows the elements inside of it. (str (vec (map identity [1 2 3]))) "[1 2 3]" Hope that makes sense. -Patrick -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
