Thanks Howard. Another great answer.

Morten

On Nov 12, 2:58 am, Howard Lewis Ship <hls...@gmail.com> wrote:
> Symbols are late resolved to functions.
>
> (def t (fn ...)) means define a Var bound to symbol t, and store the
> function in it. In JVM terms, the function becomes a new class that is
> instantiated.
>
> (t (dec x)) means locate the Var bound to symbol t -- at execution
> time (not compilation time) --- de-reference the function object
> stored there and invoke it.
>
> In fact, t can be temporarily rebound (using the binding macro) or
> even completely replaced (using alter-var-root!) at any time. The Var
> remains the same but the contents of the Var are changed.
>
> Because of how Clojure is structured, the Var object need only be
> resolved from the symbol once (in the generated Java bytecode, the Var
> appears as a static final field).
>
>
>
> On Wed, Nov 11, 2009 at 5:17 AM, mbrodersen <morten.broder...@gmail.com> 
> wrote:
> > A quick question about how closures work in Clojure.
>
> > In this simple recursive expression:
>
> > (def t (fn [x] (if (zero? x) 0 (+ x (t (dec x))))))
>
> > The fn special form is evaluated within a context where t is not yet
> > bound.
>
> > t is only bound AFTER fn has captured its environment.
>
> > In other words, the closure captured by fn doesn't know anything about
> > t (or maybe only that t is unbound).
>
> > And yet it still works if I call t:
>
> > (t 5) => 15
>
> > My question is how Clojure ensures that t is bound to the closure
> > after the closure has already been captured?
>
> > Thanks
> > Morten
>
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> --
> Howard M. Lewis Ship
>
> Creator of Apache Tapestry
>
> The source for Tapestry training, mentoring and support. Contact me to
> learn how I can get you up and productive in Tapestry fast!
>
> (971) 678-5210http://howardlewisship.com

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