A quick question about how closures work in Clojure. In this simple recursive expression:
(def t (fn [x] (if (zero? x) 0 (+ x (t (dec x)))))) The fn special form is evaluated within a context where t is not yet bound. t is only bound AFTER fn has captured its environment. In other words, the closure captured by fn doesn't know anything about t (or maybe only that t is unbound). And yet it still works if I call t: (t 5) => 15 My question is how Clojure ensures that t is bound to the closure after the closure has already been captured? Thanks Morten -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
