2009/4/22 Michael Wood <esiot...@gmail.com>:
>
> On Wed, Apr 22, 2009 at 4:57 PM, samppi <rbysam...@gmail.com> wrote:
>>
>> Let's say I have a sequence of integers:
>>  (def a (3 9 1 5 102 -322 ...))
>>
>> Is there a function for inserting an object—let's say :foo—after
>> elements that fulfill a certain predicate?
>> Furthermore, I mean inserting :foo after any block of elements that
>> fulfill it:
>>
>>  (mystery-function (partial > 6) a) ; -> (3 :foo 9 1 5 :foo 102
>> -322 :foo ...)
>>
>> Is it possible to do this without a loop?
>
> This depends on what you mean by "without a loop" I suppose.  There
> surely has to be a loop somewhere, doesn't there?
>
> Although there's no explicit loop in Laurent's solution, there is a
> (recursive) loop in the definition of partition-by.
>
> I wasn't sure what you meant by "inserting :foo after any block of
> elements that fulfill it", so this was my attempt at a solution:
>
> (defn insert-right-if [ins coll f]
>  (cond (empty? coll) coll
>       (f (first coll))
>         (lazy-seq
>          (cons (first coll) (cons ins (insert-right-if ins (rest coll) f))))
>       :else (lazy-seq
>              (cons (first coll) (insert-right-if ins (rest coll) f)))))
>
> This will insert ins after every element for which (f element) returns
> true, i.e. not quite what you want.
>
> Laurent's solution breaks with a large sequence:
> user=> (take 10 (mystery-function (partial > 6) (iterate inc 0) :foo))

You're right. The use of partition-by here will never the first group.


> java.lang.OutOfMemoryError: Java heap space (NO_SOURCE_FILE:0)
> user=> (nth (mystery-function (partial > 6) (iterate inc 0) :foo) 100000000)
> java.lang.OutOfMemoryError: Java heap space (NO_SOURCE_FILE:0)
>
> Mine (although it's not quite the right answer) handles this without
> running out of memory:
> user=> (nth (insert-right-if :foo (iterate inc 0) (partial > 6)) 100000000)
> 99999994
>
> --
> Michael Wood <esiot...@gmail.com>
>
> >
>

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