(chan) is not a channel with an unbounded buffer. It is a channel with *no* buffer and needs to rendezvous putters and takers 1-to-1. (Additionally it will throw an exception if more than 1024 takers or putters are enqueued waiting)
On Wednesday, July 3, 2019 at 7:14:46 AM UTC-4, Ernesto Garcia wrote: > > You can create a unbound channel with (chan), but not if you use a > transducer; (chan nil (filter odd?)) will raise an error that no buffer > is provided. Why is this the case? > > Why the enforcement of all channels to be bound? In a program, there will > be channels that propagate to other channels, so only channels at the > boundaries would require to be bound? > > Channel limits are also much dependent on the particular process and > environment. How would we write generic code that creates channels, if > those need to be bound to limits unknown? > > Thanks, > Ernesto > -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en --- You received this message because you are subscribed to the Google Groups "Clojure" group. To unsubscribe from this group and stop receiving emails from it, send an email to clojure+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/clojure/12cf0bf8-dafd-429b-a2d2-3875f579f1c1%40googlegroups.com. For more options, visit https://groups.google.com/d/optout.
