2017-09-06 10:35 GMT+02:00 Mark Engelberg <mark.engelb...@gmail.com>:

> You could do that by calling vec on it.  But you'd want to move the whole
> let clause outside of the defn, so it is only evaluated once, not every
> time the function is called.
>

​Wen the function is finished. ;-)
​



> But best, as I said earlier, is just to let chars be "0123456789ABCDEF".
> You can call nth on strings, so this is the most efficient way to do a
> fixed sequence of specific characters.
>

​The reason I use range is that in the future I am going to use long ranges
and I think then a range is better as a long string. But that is something
to think about.

On Wed, Sep 6, 2017 at 1:13 AM, Cecil Westerhof <cldwester...@gmail.com>
> wrote:
>
>> Answering my own question. ;-)
>>
>> 2017-09-06 9:58 GMT+02:00 Cecil Westerhof <cldwester...@gmail.com>:
>>
>>> The next step is that I want to use hexadecimal numbers. So I should use
>>> (range (int \0) (inc (int \9))) combined with (range (int \A) (inc (int
>>> \F))).
>>> How would I do that?
>>>
>>
>> ​    (concat (range (int \0) (inc (int \9))) (range (int \A) (inc (int
>> \F))))
>> ​
>>
>> ​By the way. I am using a lazy sequence here. Could it be updated with
>> using a vector when creating very long strings, or is that not a
>> significant performance increase?​
>>
>
-- 
Cecil Westerhof

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