Answering my own question. ;-)

2017-09-06 9:58 GMT+02:00 Cecil Westerhof <cldwester...@gmail.com>:

> The next step is that I want to use hexadecimal numbers. So I should use
> (range (int \0) (inc (int \9))) combined with (range (int \A) (inc (int
> \F))).
> How would I do that?
>

​    (concat (range (int \0) (inc (int \9))) (range (int \A) (inc (int
\F))))
​

​By the way. I am using a lazy sequence here. Could it be updated with
using a vector when creating very long strings, or is that not a
significant performance increase?​

-- 
Cecil Westerhof

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