Hello, Does it also mean that the following use case will work with *reload-all* :
- x.y.z is a lib that is made of two files : x/y/z.clj, and x/y/z1.clj , and z.clj loads z1.clj - x.y.z is compiled - z1.clj is modified - x.y.z is compiled => even if x/y/z.clj nor x/y/z__init.class are in sync, the changes in z1.clj will be reloaded, because z1.clj will be forced to be reloaded from source file ? Is my understanding correct ? If so, ++1 for this ! Regards, -- Laurent 2009/2/6 Stephen C. Gilardi <squee...@mac.com> > > On Feb 6, 2009, at 8:28 AM, Stephen C. Gilardi wrote: > > When *reload-all* is true, RT.load() will (re)load all libs from their >> ".clj" files even if they're already loaded. >> > > To clarify: > > When *reload-all* is true, RT.load will (re)load any lib it is asked to > load from the lib's ".clj" file even if the lib is already loaded. > > --Steve > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en -~----------~----~----~----~------~----~------~--~---
