On Thu, Dec 18, 2008 at 9:08 PM, Stuart Sierra <the.stuart.sie...@gmail.com> wrote: > > On Dec 18, 6:05 pm, "Mark Volkmann" <r.mark.volkm...@gmail.com> wrote: >> If I understand correctly, >> >> (are (< 1 2, 5 7)) >> >> is equivalent to >> >> (is (< 1 2)) >> (is (< 5 7)) > > Not exactly. The first argument to "are" is a template expression, > which is sort of like #(). The arguments to the template are symbols > named "_1", "_2", "_3", "_4", and so on. The remaining arguments of > "are" fill in the arguments to the template. So: > > (are (< _1 _2) 5 7 8 10) > ;=> expands to (do (is (< 5 7)) (is (< 8 10)) > > Make sense? This is roughly equivalent to > (map (fn [x y] (is (< x y))) [[5 7] [8 10]]) > but it happens at compile time.
Thanks! I understand it now. There's still the issue though that if I use it incorrectly like this: (are < 1 2, 5 7) it hangs forever instead of giving me an error. -- R. Mark Volkmann Object Computing, Inc. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en -~----------~----~----~----~------~----~------~--~---
