On Dec 18, 6:05 pm, "Mark Volkmann" <r.mark.volkm...@gmail.com> wrote: > If I understand correctly, > > (are (< 1 2, 5 7)) > > is equivalent to > > (is (< 1 2)) > (is (< 5 7))
Not exactly. The first argument to "are" is a template expression, which is sort of like #(). The arguments to the template are symbols named "_1", "_2", "_3", "_4", and so on. The remaining arguments of "are" fill in the arguments to the template. So: (are (< _1 _2) 5 7 8 10) ;=> expands to (do (is (< 5 7)) (is (< 8 10)) Make sense? This is roughly equivalent to (map (fn [x y] (is (< x y))) [[5 7] [8 10]]) but it happens at compile time. -Stuart Sierra --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en -~----------~----~----~----~------~----~------~--~---
