On Tuesday 16 December 2008 18:10, wubbie wrote: > Hello, > > My question is that conj takes two argument and how conj finds > the first argument? Is it somehow provided by commute?
Consider the documentation for (commute ...) (at <http://clojure.org/api>): -==--==--==--==--==--==--==--==--==--==--==--==--==--==--==- commute ref fun & args) Must be called in a transaction. Sets the in-transaction-value of ref to: (apply fun in-transaction-value-of-ref args) and returns the in-transaction-value of ref. At the commit point of the transaction, sets the value of ref to be: (apply fun most-recently-committed-value-of-ref args) Thus fun should be commutative, or, failing that, you must accept last-one-in-wins behavior. commute allows for more concurrency than ref-set. -==--==--==--==--==--==--==--==--==--==--==--==--==--==--==- In both cases, the first argument to the "fun" argument to (commute ...) is implicitly either the "in-transacxtion-value-of-ref" or "most-recently-committed-value-of-ref". All other / subsequent arguments are those appearing as the 3rd and subsequent arguments to (commute ...). > Thanks, > sun Randall Schulz --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en -~----------~----~----~----~------~----~------~--~---
