On Dec 8, 5:06 pm, "Frantisek Sodomka" <[EMAIL PROTECTED]> wrote: > I just wonder - how do you define "all-true" using "are"? Since "are" > always makes pairs for predicate, it might not be possible.
Hi Frantisek, The short answer is, you don't. :) Just use "is" for now. I'll consider making (is (and ...)) a recognized form, though. I'm not certain about "are" yet, but I figured I had to offer at least a little sugar. Maybe what it really needs is template-style argument, like Rich has suggested for condp: (are (pred %1 %2) a1 b1 a2 b2) -Stuart Sierra --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/clojure?hl=en -~----------~----~----~----~------~----~------~--~---
