Am 21.04.2013 um 17:50 schrieb Gregory Farnum <g...@inktank.com>:

> On Sun, Apr 21, 2013 at 12:39 AM, Stefan Priebe - Profihost AG
> <s.pri...@profihost.ag> wrote:
>> I know it is 100*numofosds/replfactor. But I also read somewhere that it 
>> should be a value of 2^X. It this still correct? So for 24 osds and repl 3 
>> 100*24/3 => 800 => to be 2^X => 1024?
> 
> PG counts of 2^x ensure that each PG covers exactly the same amount of
> hash space. This can improve your distribution, but at reasonable PG
> counts is definitely not critical — I might use that if I were going
> to do less than 50 PGs/OSD like you are, but it shouldn't be
> necessary.

But going under 50pgs per pool is suggested at the ceph docs by deviding 
through rep factor.

Stefan

> -Greg
> Software Engineer #42 @ http://inktank.com | http://ceph.com
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