On Sun, Apr 21, 2013 at 12:39 AM, Stefan Priebe - Profihost AG
<s.pri...@profihost.ag> wrote:
> I know it is 100*numofosds/replfactor. But I also read somewhere that it 
> should be a value of 2^X. It this still correct? So for 24 osds and repl 3 
> 100*24/3 => 800 => to be 2^X => 1024?

PG counts of 2^x ensure that each PG covers exactly the same amount of
hash space. This can improve your distribution, but at reasonable PG
counts is definitely not critical — I might use that if I were going
to do less than 50 PGs/OSD like you are, but it shouldn't be
necessary.
-Greg
Software Engineer #42 @ http://inktank.com | http://ceph.com
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