[Exceptionally top-posting...]
There are two modules each containing eight pulse transformers. That's it.
The left module has the cover removed.
No memory, no register. This board is from 1971, so it would contain some
TTL FFs or RAM (e.g. 7489) for registers.
Christian
On Wed, 1 Feb 2017, dwight wrote:
I think it is a register board. Something
to hold data through a power down.
Dwight
On Feb 1, 2017, at 1:02 PM, Paul Koning <paulkon...@comcast.net> wrote:
On Feb 1, 2017, at 11:57 AM, Rick Bensene <ri...@bensene.com> wrote:
Mr. Havermout wrote:
Can someone identify this circuit board? It's some sort of magnetic core
memory. I've had this for ages and I've always wondered what it is and
where it comes from.
http://lookpic.com/O/i2/366/iAFq4mLF.jpeg
Whatever this was, it appears that it has been scavenged for parts over time.
Many components appear to be missing.
It seems to me from looking at the board carefully that it could be a small
wire-rope ROM, or, perhaps the cores (one module has its cover removed exposing
the large ferrite rings) serve as pulse transformers for magnetic core that
resides on another circuit board.
If it is a small wire-rope read-only memory, it appears that it could be a
16x16 ROM, perhaps hard wired for some kind of small bootstrap loader or the
like.
It looks like there are 16 wire drivers (two of the driver transistors are
missing), and 16 sense amplifiers.
If it's a core-rope ROM, which seems plausible, then it would be 256 x 16. Core rope
uses 2 select ("inhibit") lines/drivers per address bit. So 16 drivers means 8
address bits, i.e., 2^8 words.
Never mind, that was all wrong. It takes only 2*n wires to select one of 2^n
cores in a core-rope ROM, so far that was correct. But the number of ROM words
equals the number of cores (obviously). So if there are 16 cores that would
mean 16 words, but it also means that only 8 drivers are needed (4 address
bits). So there's a puzzle.
paul
