8= 00001000
10= 00001010
Now move from left to right..Stop at the LAST COMMON bit. That is you
boundary
here 0 0 0 0 1 0 <<<stop there.
0 0 0 0 1 0 = 8
that should should give you 20 mask length. This length will cover .8,.9,.10,.11
===============================
/22 is the better .
You can do /20 also. but it will cover some extra networks too. and that will
cover .15,.14,13,.12,.11,.10,.9.8,.7,.6,.5,.4,.3,.2,.1,.0
From: [email protected]
To: [email protected]
Date: Fri, 18 Sep 2009 21:10:43 +0430
Subject: [OSL | CCIE_RS] Summarization,
Hello Dears,
Anyone can please help with the following issue, How the summary of these two
addresses " 155.1.8.8, 155.1.10.10" became /22?according to my calculation it
should be /20
Best regards,
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