On 9/2/15 11:19 AM, Greg Wooledge wrote:
> On Wed, Sep 02, 2015 at 10:16:14AM -0500, Dennis Williamson wrote:
>> The $ is implied.
>
> That is completely absurd. (And wrong.)
Not exactly. When the arithmetic evaluator encounters a token that is of
the form of a shell identifier (`bar'), in a context where an operand is
needed, it treats it as a shell variable and looks up the variable's
value. In that sense, it's an expansion.
The difference between bash and dash is what each shell does with that
value.
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU c...@case.edu http://cnswww.cns.cwru.edu/~chet/
