On 2014-07-15 20:09:40, Juergen Sauermann wrote:
> Except that (not so obviously) :
> 
> 
>       1E¯15 = 1E¯14
> 0

Sorry, my mistake.  You're, of course, right.
Current (r376) behaviour seems to be correct with one exception:

      1E¯15 = 1E¯14
0
      1E¯15J0 = 1E¯14J0
1

Both should be zero, because it's exactly the same number.


-k

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