Randal L. Schwartz wrote:
>>>>>> "Rob" == Rob Dixon <rob.di...@gmx.com> writes:
>
> Rob> I tested the similar
>
> Rob> my @data = do {
> Rob> open my $fh, '<', $file or die $!;
> Rob> <$fh>;
> Rob> };
>
> Rob> a while ago, but not on v5.10. I will see if I can find time to try it
> again.
>
> Ahh, but that's very different. My suspicion is that both the last-expr
> scalar of the block and the $result scalar will share the same single
> payload, similar to how:
>
> $x = $y
>
> doesn't actually copy the *content*... just the scalar wrapper around
> the content.
It appears not, but there is certainly room for optimisation in the case where
scalar data both loses and gains a reference count at the end of a block like
this.
R
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